Charles A. Foote American politician
Charles A. Foote is a 43 years old American politician from Newburgh, New York. Charles A. Foote was born on April 15, 1785 (died on August 01, 1828, he was 43 years old) in Newburgh, New York.
About
No, he died on 08/01/1828, 195 years ago. He was 43 years old when he died. He died in Delhi
Education
He graduated from Union College
What was Charles's zodiac sign?Charles A. Foote zodiac sign was aries.
Other facts about Charles A. Foote
| Place of death | Delhi |
|---|---|
| Party | Democratic-Republican Party |
| Region | New York's 11th congressional district |
| Work location | Washington, D.C. |
| Member of political party | Democratic-Republican Party |
| Date of death | 1828-08-01T00:00:00Z |
| Position held | United States Representative |
| Country of citizenship | United States Of America |
| Place of birth | Newburgh |
| Given name | Charles |
| Languages spoken, written or signed | English |
Charles A. Foote Is A Member Of
Comments
There are no comments yet.
