Henry Danby Seymour British politician
Henry Danby Seymour is a 57 years old British politician from . Henry Danby Seymour was born on July 01, 1820 (died on August 04, 1877, he was 57 years old) in .
About
No, he died on 08/04/1877, 146 years ago. He was 57 years old when he died.
Family
His mother is Jane Hopkinson and his father is Henry Seymour. His mother died at the age of (Henry was 48 years old). () and Henry Seymour was 2 years old when Henry born.
Parents
Mother: Jane Hopkinson
Father: Henry Seymour
Brother
Henry Danby Seymour had 1 sibling. Alfred (22 years younger)
What was Henry's zodiac sign?Henry Danby Seymour zodiac sign was cancer.
Other facts about Henry Danby Seymour
| Family name | Seymour. Show people with the surname Seymour |
|---|---|
| Writing languages | English |
| Languages spoken, written or signed | English |
| Name in native language | Henry Danby Seymour |
| Country of citizenship | United Kingdom Of Great Britain And Ireland |
| Given name | Henry |
| Date of death | 1877-08-04T00:00:00Z |
| Work location | London |
| Position held | Member Of The 19th Parliament Of The United Kingdom , elected in: 1865 United Kingdom general election , end cause: dissolution of parliament , electoral district: Poole , end time: 1868-11-11T00:00:00Z , start time: 1865-07-11T00:00:00Z |
