George Arthur Cecil Maunsell
George Arthur Cecil Maunsell is a 79 years old from . George Arthur Cecil Maunsell was born on March 26, 1911 (died on December 26, 1990, he was 79 years old) in .
About
No, he died on 12/26/1990, 33 years ago. He was 79 years old when he died.
Family
His mother is Amabel Staveley Marindin and his father is Arthur Persse Gabbett Maunsell. His mother died at the age of (George was 51 years old). When George born she was 30 years old. () and Arthur Persse Gabbett Maunsell was 34 years old when George born.
Parents
Mother: Amabel Staveley Marindin
Father: Arthur Persse Gabbett Maunsell
Wife
Mary Gertrude Lawler
He married with Mary Gertrude Lawler on Tuesday, July 23rd, 1940. George Arthur Cecil Maunsell was 29 and Mary Gertrude Lawler was 22 years old. Married for 83 years, 11 months.
Children
He had three children, Christopher (62) , Patricia (65) and Philippa (74) . When his first child, Christopher Arthur John Maunsell, was born, George Arthur Cecil Maunsell was 30 years old.
What was George's zodiac sign?George Arthur Cecil Maunsell zodiac sign was aries.
Other facts about George Arthur Cecil Maunsell
| Date of death | 1990-12-26T00:00:00Z |
|---|---|
| Military rank | Lieutenant Colonel |
| Given name | George |
